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8a^2+42a+49=0
a = 8; b = 42; c = +49;
Δ = b2-4ac
Δ = 422-4·8·49
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{196}=14$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(42)-14}{2*8}=\frac{-56}{16} =-3+1/2 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(42)+14}{2*8}=\frac{-28}{16} =-1+3/4 $
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